Question
Aggiornato il
1 mar 2021

  • Cinese semplificato (Mandarino)
  • Inglese (Stati Uniti)
  • Francese (Francia)
  • Tedesco
Domande Inglese (Stati Uniti)

___ Navigation has confirmed the parachute has deployed and we have seen a significant celebration. The velocity the current velocity is 200 meters per second and the altitude is about 12 km to the surface of Mars. ___ Perseverance slow to __ speed and he _ separated that's allowed both radar and camera can take their first look at the surface. Current velocity is 145 meters per second and the altitude is about ten k.. nine and a half km above the surface. __ solutions 3.3 meters per second. Altitude 7.4 km. Now have radar locked on the ground. The current velocity is about 100 meters per second, 6.6 km above the surface of Mars.

Could you help to check my work? Thanks

Risposte
Condividi questa domanda
Leggi ulteriori commenti

  • Cinese semplificato (Mandarino)

  • Cinese semplificato (Mandarino)

  • Cinese semplificato (Mandarino)

  • Cinese semplificato (Mandarino)

  • Cinese semplificato (Mandarino)

  • Cinese semplificato (Mandarino)

  • Inglese (Stati Uniti)

  • Cinese semplificato (Mandarino)
[Novità] Ehi tu! Dico a te che stai imparando una lingua!

Condividi questa domanda
___ Navigation has confirmed the parachute has deployed and we have seen a significant celebration. The velocity the current velocity is 200 meters per second and the altitude is about 12 km to the surface of Mars. ___ Perseverance slow to __ speed and he _ separated that's allowed both radar and camera can take their first look at the surface. Current velocity is 145 meters per second and the altitude is about ten k.. nine and a half km above the surface. __ solutions 3.3 meters per second. Altitude 7.4 km. Now have radar locked on the ground. The current velocity is about 100 meters per second, 6.6 km above the surface of Mars. 

Could you help to check my work? Thanks
domande simili
Domande suggerite
Newest Questions (HOT)
Domande Recenti
Previous question/ Next question